ERDC/CHL CHETN-III-67
September 2003
2.026
⎛H⎞
= 0.639 (0.6)2.026 = 0.2270
A0 = 0.639 ⎜ ⎟
⎝h⎠
-0.391
⎛H⎞
= 0.180 (0.6)-0.391 = 0.2198
A1 = 0.180 ⎜ ⎟
⎝h⎠
Finally, the nondimensional wave momentum flux parameter is calculated from Equation 5 as
- A1
⎛ MF ⎞
⎛ h ⎞
= 0.2270 (0.0073)-0.2198 = 0.669
= A0 ⎜ 2 ⎟
⎜
⎟
ρ gh2 ⎠max
⎝ gT ⎠
⎝
Calculate the Maximum Depth-Integrated Wave Momentum Flux: The dimensional value of
maximum depth-integrated wave momentum flux per unit length along the wave crest is obtained
simply as
⎛M ⎞
(MF)max = (ρ g) (h2) ⎜ F2 ⎟ = (64 lb/ft3) (15 ft)2 (0.669) = 9,634 lb/ft
⎜ ρgh ⎟
⎝
⎠max
Example: Solitary Wave Momentum Flux Parameter
Find: The nondimensional wave momentum flux parameter and the corresponding maximum
depth-integrated wave momentum flux per unit length of wave crest for the specified solitary wave.
Given:
h = 15 ft
Water depth
H = 9 ft
Solitary wave height
g = 32.2 ft/s2
ρg = 64 lb/ft3
Specific weight of sea water
Calculate the Wave Momentum Flux Parameter: This solitary wave has the same relative wave
height as the previous example, i.e.,
H 9 ft
h = 15 ft = 0.6
Using this value of H/h, determine the coefficients M and N from Equations 9 and 10, respectively:
0.44
⎧
⎛ H ⎞⎤ ⎫
⎡
= 0.98 {tanh [2.24 (0.6)]}0.44 = 0.923
M = 0.98 ⎨tanh ⎢2.24 ⎜ ⎟⎥ ⎬
⎝ h ⎠⎦ ⎭
⎣
⎩
10